TSTP Solution File: NUM726^1 by cocATP---0.2.0
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% File : cocATP---0.2.0
% Problem : NUM726^1 : TPTP v7.0.0. Released v3.7.0.
% Transfm : none
% Format : tptp:raw
% Command : python CASC.py /export/starexec/sandbox2/benchmark/theBenchmark.p
% Computer : n066.star.cs.uiowa.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2609 0 2.40GHz
% Memory : 32218.625MB
% OS : Linux 3.10.0-693.2.2.el7.x86_64
% CPULimit : 300s
% DateTime : Mon Jan 8 13:11:33 EST 2018
% Result : Theorem 0.08s
% Output : Proof 0.08s
% Verified :
% SZS Type : None (Parsing solution fails)
% Syntax : Number of formulae : 0
% Comments :
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%----WARNING: Could not form TPTP format derivation
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%----ORIGINAL SYSTEM OUTPUT
% 0.00/0.03 % Problem : NUM726^1 : TPTP v7.0.0. Released v3.7.0.
% 0.00/0.03 % Command : python CASC.py /export/starexec/sandbox2/benchmark/theBenchmark.p
% 0.02/0.23 % Computer : n066.star.cs.uiowa.edu
% 0.02/0.23 % Model : x86_64 x86_64
% 0.02/0.23 % CPU : Intel(R) Xeon(R) CPU E5-2609 0 @ 2.40GHz
% 0.02/0.23 % Memory : 32218.625MB
% 0.02/0.23 % OS : Linux 3.10.0-693.2.2.el7.x86_64
% 0.02/0.23 % CPULimit : 300
% 0.02/0.23 % DateTime : Fri Jan 5 13:15:50 CST 2018
% 0.02/0.23 % CPUTime :
% 0.08/0.25 Python 2.7.13
% 0.08/0.52 Using paths ['/home/cristobal/cocATP/CASC/TPTP/', '/export/starexec/sandbox2/benchmark/', '/export/starexec/sandbox2/benchmark/']
% 0.08/0.52 FOF formula (<kernel.Constant object at 0x2b627ca5f680>, <kernel.Type object at 0x2b627ca5f320>) of role type named frac_type
% 0.08/0.52 Using role type
% 0.08/0.52 Declaring frac:Type
% 0.08/0.52 FOF formula (<kernel.Constant object at 0x2b627ca5f4d0>, <kernel.Constant object at 0x2b627ca5fd40>) of role type named x
% 0.08/0.52 Using role type
% 0.08/0.52 Declaring x:frac
% 0.08/0.52 FOF formula (<kernel.Constant object at 0x2b627cb437e8>, <kernel.Constant object at 0x2b627ca5fd40>) of role type named y
% 0.08/0.52 Using role type
% 0.08/0.52 Declaring y:frac
% 0.08/0.52 FOF formula (<kernel.Constant object at 0x2b627ca5f680>, <kernel.Type object at 0x2b627ca5b440>) of role type named nat_type
% 0.08/0.52 Using role type
% 0.08/0.52 Declaring nat:Type
% 0.08/0.52 FOF formula (<kernel.Constant object at 0x2b627ca5f050>, <kernel.DependentProduct object at 0x2b627ca5f320>) of role type named ts
% 0.08/0.52 Using role type
% 0.08/0.52 Declaring ts:(nat->(nat->nat))
% 0.08/0.52 FOF formula (<kernel.Constant object at 0x2b627ca5fd40>, <kernel.DependentProduct object at 0x2b627ca5ba70>) of role type named num
% 0.08/0.52 Using role type
% 0.08/0.52 Declaring num:(frac->nat)
% 0.08/0.52 FOF formula (<kernel.Constant object at 0x2b627ca5f680>, <kernel.DependentProduct object at 0x2b627ca5b488>) of role type named den
% 0.08/0.52 Using role type
% 0.08/0.52 Declaring den:(frac->nat)
% 0.08/0.52 FOF formula (((eq nat) ((ts (num x)) (den y))) ((ts (num y)) (den x))) of role axiom named e
% 0.08/0.52 A new axiom: (((eq nat) ((ts (num x)) (den y))) ((ts (num y)) (den x)))
% 0.08/0.52 FOF formula (((eq nat) ((ts (num y)) (den x))) ((ts (num x)) (den y))) of role conjecture named satz38
% 0.08/0.52 Conjecture to prove = (((eq nat) ((ts (num y)) (den x))) ((ts (num x)) (den y))):Prop
% 0.08/0.52 Parameter nat_DUMMY:nat.
% 0.08/0.52 We need to prove ['(((eq nat) ((ts (num y)) (den x))) ((ts (num x)) (den y)))']
% 0.08/0.52 Parameter frac:Type.
% 0.08/0.52 Parameter x:frac.
% 0.08/0.52 Parameter y:frac.
% 0.08/0.52 Parameter nat:Type.
% 0.08/0.52 Parameter ts:(nat->(nat->nat)).
% 0.08/0.52 Parameter num:(frac->nat).
% 0.08/0.52 Parameter den:(frac->nat).
% 0.08/0.52 Axiom e:(((eq nat) ((ts (num x)) (den y))) ((ts (num y)) (den x))).
% 0.08/0.52 Trying to prove (((eq nat) ((ts (num y)) (den x))) ((ts (num x)) (den y)))
% 0.08/0.52 Found e__eq_sym:=((((eq_sym nat) ((ts (num x)) (den y))) ((ts (num y)) (den x))) e):(((eq nat) ((ts (num y)) (den x))) ((ts (num x)) (den y)))
% 0.08/0.52 Found e__eq_sym as proof of (((eq nat) ((ts (num y)) (den x))) ((ts (num x)) (den y)))
% 0.08/0.52 Got proof ((((eq_sym nat) ((ts (num x)) (den y))) ((ts (num y)) (den x))) e)
% 0.08/0.52 Time elapsed = 0.003283s
% 0.08/0.52 node=0 cost=0.000000 depth=0
% 0.08/0.52::::::::::::::::::::::
% 0.08/0.52 % SZS status Theorem for /export/starexec/sandbox2/benchmark/theBenchmark.p
% 0.08/0.52 % SZS output start Proof for /export/starexec/sandbox2/benchmark/theBenchmark.p
% 0.08/0.52 ((((eq_sym nat) ((ts (num x)) (den y))) ((ts (num y)) (den x))) e)
% 0.08/0.52 % SZS output end Proof for /export/starexec/sandbox2/benchmark/theBenchmark.p
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